School!

[noodles]

[Kinokokao]

[Rain]

[Kinokokao]

[negzee]

I almost always use unless some other specific format is required. In the absence of year, I spell out the name of the month and zero-pad the day of month to two digits. These forms are longer, I suppose, but they are unambiguous.

[Kinokokao]

If at all possible I prefer May 9th since "May" is such a short name for a month anyway.

Although when I was little I struggled with it since, due to my speech problems, it came out as "May Knife"

[noodles]

I know of your speech problems

they are pretty cute

[Kinokokao]

I GONNA GE ON E US OUWEEEENNN!

[scy]

Application process is a lot of formality and not a lot of nitpick. Just saying. I got into everywhere I applied to and I didn't put much effort into mine.

[spoiler]Sans Caltech since I figured they'd rape me for not being like #1 in my class with a near perfect SAT but, hey, they still admitted me.

In retrospect, I guess my other applications don't count since I was auto-admitted due to SAT scores and class rank (Texas so we have the whole top 10% auto-admit to public universities).[/spoiler]

In other news, probably bombed an exam. In my defense, if we have questions like find primitive roots and decrypt with no calculator, go fuck yourself.

[spoiler]Primitive root checking is tedious >>

e.g., our exam was show 7 is a primitive root of 11 and show that 3 is not, the work is:

7 ^ 1 mod 11 = 7
7 ^ 2 mod 11 = 49 = 5
7 ^ 3 mod 11 = 343 = 2
7 ^ 4 mod 11 = 2401 = 4
...
...
...
7 ^ 10 mod 11 = yeahbignumber = 1

If it is a primitive root, then 7^1 ... 7^10 will yield 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 somewhere in the spread; if it doesn't, then it is not a primitive root (in the case of 3, it goes 3, 9, 5, 4, 1 and repeats).
Or pretty much:
a ^ i mod n
Where n is prime and i goes from 1 to (n-1).

...yeah.

Decryption question was simple RSA decryption with encoded message c = 58, n = 77, and decryption = 13.

...so we had:
m = c ^ d mod n
m = 58 ^ 13 mod 77

...fuck you, I am not hand working out 58 ^ 13.

T.T[/spoiler]

[Kinokokao]

lol numbers

Which reminds me of this beautiful quote from class last week:

Columbus was like a History major... 12,000 miles, 5,000 miles, eh, what's the difference.

All the history majors chuckled.

I don't expect you to understand.

[scy]

Why wouldn't I get it? >>

[spoiler]Incidentally, I have a Racial and Ethnic Relations class and boy, we reamed the fuck out of Columbus for awhile. Thanksgiving is another "oh man this is getting depressing" subject too.[/spoiler]

Edit: It's not like 'getting numbers' makes what I had on my exam this morning any easier; it's just silly to expect us to do calculations in the billions (or in case of 58 ^ 13, something like 25 digits) by hand. 7 ^ 10 wasn't so bad (9 digits) but still >>

[Kinokokao]

[Rain]

BUMPAGE GUYS

CHEMISTRY LAB HALP ON CALORIMETRY AND ENTHALPYYY?
[spoiler]
I did a lab in Chem and I was wondering if anyone remembered their thermodynamics and calorimetry to help me figure out the enthalpy for the neutralization rxn of HCl and NaOH, given that you had 25cm^3 of 1.00M of both. My group and I also calculated the initial temperatures of HCl and NaOH, as well as the solution's final temperature, so they're about ~21C HCl, ~23C NaOH, ~27C final temp.

I started by converting the 25cm^3 HCl and NaOH into grams so I ended up with 50g (together). Then using q=m*C*(Tf-Ti), I plugged in my given and...

q=(50g)*(4.18J/gC)*(Tf-Ti)

Yeah, what do I use for Tf-Ti ? 27 - ?
And I'm just assuming we can use water's specific heat because... I have no idea what else to use as we weren't given anything else.
(And hey, the practice problems were like that so...)

Am I even doing this right? XD;[/spoiler]

[Kinokokao]

[Maxine MagicFox]